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Suppose the quantity (in grams ) of a radioactive substance present at time t is Q(t)=2744(7^(-0.3t)) How much will be present in 4 months?

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Final answer:

Approximately 90.15 grams of the radioactive substance will be present after 4 months.

Step-by-step explanation:

To find the quantity of the radioactive substance present after 4 months, we need to substitute the value of t with 4 in the given formula:

Q(t) = 2744(7^(-0.3t))

Q(4) = 2744(7^(-0.3*4))

Q(4) = 2744(7^(-1.2))

Q(4) = 2744(0.03284)

Q(4) = 90.1466 grams

Therefore, approximately 90.15 grams of the radioactive substance will be present after 4 months.

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