Question

springs ab and bc have k = 500 n/m and a undeformed length of 3 m. what force f will cause the horizontal displacement distance d = 1.5 m?

Answer 1

To find the force required to displace two springs each by 1.5 m with a spring constant of 500 N/m, we use Hooke's Law (F = kx), resulting in a total force of 1500 N.

Step-by-step explanation:

The student is asking about the force required to displace two springs with a spring constant (k) of 500 N/m and undeformed lengths of 3 m by a distance of 1.5 m each. To find the force F, we need to use Hooke's Law, which states F = kx, where x is the displacement of the spring from its equilibrium position. Since each spring is displaced by 1.5 m, we can calculate the force for one spring and double it for both springs.

For one spring, the force would be: F = 500 N/m * 1.5 m = 750 N. Since both springs are displaced the same amount, the total force needed will be double that amount, so the total force F for displacing both springs 1.5 m is 750 N * 2 = 1500 N.