Question

An object accelerates from rest, with a constant acceleration of 14.5 m/s^2, what will its velocity be after 92 s?

a) 1339 m/s
b) 1445 m/s
c) 1318 m/s
d) 1450 m/s

Answer 1

Using the kinematic equation v = u + at, where initial velocity u is 0, acceleration a is 14.5 m/s², and time t is 92 seconds, the final velocity v is calculated to be 1334 m/s. However, this answer does not match the provided options, suggesting a discrepancy in the question or choices.

Step-by-step explanation:

The question you've asked is about finding the final velocity of an object that accelerates from rest with a constant acceleration. To calculate this, we use one of the kinematic equations that relates velocity, acceleration, and time:

v = u + at

Here, v is the final velocity, u is the initial velocity (which is 0 since the object starts from rest), a is the constant acceleration, and t is the time. For your specific problem, the acceleration is given as 14.5 m/s² and the time is 92 seconds.

Plugging the values into the equation, we have:

v = 0 + (14.5 m/s² * 92 s)

v = 1334 m/s

Therefore, the final velocity of the object after 92 seconds will be 1334 m/s. This value is not listed in the options provided, indicating a possible error, as the closest answer choice is a) 1339 m/s, which is not the correct calculation based on the provided information.