Question

How much work is needed to transfer 767.1 kC of charge in one hour through a potential rise of 567.78 V ?

Answer 1

The change in potential energy ΔU of a system where a charge q moves through a potential difference ΔV is:

`\Delta U=q\Delta V`

The work needed to move a charge q through a potential difference ΔV is the same as the change in potential energy of the system. Then, replace q=767.1kC and ΔV=567.78V to find the work needed to complete the described process:

`\begin{gathered} \Delta U=q\Delta V \\ =(767.1kC)(567.78V) \\ =435,544kJ \end{gathered}`

Therefore, the amount of work needed to complete such a process is approximaely 435,544 kiloJoules.