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If a ball is thrown into the air with a velocity of 58 ft/s, its height (in feet) after t seconds is given by H=58t-11t². Find the velocity when t=4. Select one:

a. 25ft/s
b. 31ft/s
c. 27ft/s
d. 37ft/s
e. 30ft/s

1 Answer

3 votes

Final answer:

The velocity when t=4 is -30 ft/s, which is equivalent to 30 ft/s in the opposite direction.

Therefore, the correct answer is: option e). 30ft/s

Step-by-step explanation:

To find the velocity when t=4, we need to find the derivative of the height function H(t) = 58t - 11t² with respect to time.

The derivative of H(t) is the rate of change of height with respect to time, which gives us the velocity.

So, let's find the derivative:

H'(t) = 58 - 22t

Now, we can substitute t=4 into the derivative:

H'(4) = 58 - 22(4)

H'(4) = 58 - 88

H'(4) = -30

Therefore, the velocity when t=4 is -30 ft/s, which is equivalent to 30 ft/s in the opposite direction.

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