Final answer:
The balanced chemical equation for the combustion of 1-propanol with oxygen gas is C3H8O + 5O2 -> 3CO2 + 4H2O. The limiting reactant can be determined by comparing the number of moles of reactants to the stoichiometry of the balanced equation. The amount of CO2 released and the amount of excess reactant remaining can be calculated using stoichiometry and mass-to-mole conversions.
Step-by-step explanation:
The balanced chemical equation for the combustion of 1-propanol (C3H8O) with oxygen gas (O2) is:
C3H8O + 5O2 → 3CO2 + 4H2O
The reaction shows that 1 mole of 1-propanol reacts with 5 moles of oxygen gas to produce 3 moles of carbon dioxide and 4 moles of water.
To determine the limiting reactant, you need to compare the number of moles of reactants to the stoichiometry of the balanced equation and identify which reactant is in excess. The limiting reactant is the one that is completely used up, which means it limits the amount of product formed. In this case, you would need to calculate the number of moles of 1-propanol and oxygen gas and compare them.
The number of grams of CO2 released in the reaction can be calculated by converting the mass of 1-propanol to moles and then using the stoichiometry of the balanced equation to determine the moles of CO2 produced. Finally, you can convert the moles of CO2 to grams using the molar mass of CO2.
The amount of excess reactant remaining can be calculated by subtracting the amount of limiting reactant consumed from the initial amount of excess reactant.