Let's graph the following inequalities in a number line:
![\text{ 3x^^b2 - 27x \le 0}]()
First, let's factor out the equation and determine its zeros.
3x² - 27x ≤ 0
(3x² - 27x) ÷ 3 ≤ 0 ÷ 3
x² - 9x ≤ 0
x(x - 9) ≤ 0
There are two factors, x and x - 9. Thus, the solution to the inequality is:
x = 0
x - 9 = 0
x = 9
The intervals will be:
0 ≤ x ≤ 9
Putting this in a number line will be:
The answer is CHOICE B.