Final answer:
After decelerating for 5 seconds, the bicyclist's speed would be 12 m/s, and the distance traveled during this time would be 92.5 meters. The answer choices provided do not match this correct calculation.
Step-by-step explanation:
To determine the bicyclist's speed after decelerating for 5 seconds, you can use the formula for final velocity v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. In this case, the initial velocity u is +37 m/s, the acceleration a is -5 m/s2, and the time t is 5 seconds. Plugging in these values gives us 37 m/s + (-5 m/s2 * 5 s), which equals 12 m/s. To find the distance traveled during this time, use the formula s = ut + 1/2at2, where s is the distance. That gives us (37 m/s * 5 s) + 1/2 * (-5 m/s2) * (5 s)2, which results in 92.5 meters.
So, the bicyclist is traveling at 12 m/s after 5 seconds, and the distance traveled during this time is 92.5 meters. The correct answer is none of the options provided, so it seems there might have been an error in the question or the answer choices.