Question

Write each standard form6. 2x(x+3)=47. (x+1)²=08. (x+1)²=(x-4)²9. 3x(2x+5)=0

Answer 1

Given:

`\begin{gathered} 2x(x+3)=4 \\ (x+1)^2=0 \\ (x+1)^2=(x-4)^2 \\ 3x(2x+5)=0 \end{gathered}`

Required:

To write the given equations in standard form.

Step-by-step explanation:

Consider

`\begin{gathered} 2x(x+3)=4 \\ 2x^2+6x=4 \\ 2x^2+6x-4=0 \\ \\ (x+1)^2=0 \\ x^2+2x+1=0 \\ \\ (x+1)^2=(x-4)^2 \\ x^2+2x+1=x^2-8x+16 \\ x^2+2x+1-x^2+8x-16=0 \\ 10x-15=0 \\ \\ 3x(2x+5)=0 \\ 6x^2+15x=0 \end{gathered}`

Final Answer:

`\begin{gathered} 6)2x^2+6x-4=0 \\ \\ 7)x^2+2x+1=0 \\ \\ 8)10x-15=0 \\ \\ 9)6x^2+15x=0 \end{gathered}`