Answer:
25.4 g CH₄
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
Stoichiometry
- Using Dimensional Analysis
Step-by-step explanation:
Step 1: Define
1.58 mol CH₄
Step 2: Identify Conversions
[PT] Molar Mass of C - 12.01 g/mol
[PT] Molar Mass of H - 1.01 g/mol
Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol
Step 3: Convert
- Set up:

- Multiply/Divide:

Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
25.359 g CH₄ ≈ 25.4 g CH₄