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Find the values of the remaining trigonometric functions at t from the given information. sin t=5/13, cos t=-12/13

User Indu Joshi
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Final answer:

To find the values of the remaining trigonometric functions, we can use the given information of sin t = 5/13 and cos t = -12/13. Using the Pythagorean identity, sin^2 t + cos^2 t = 1, we can find sin^2 t = 25/169 and cos^2 t = 144/169. With these values, we can calculate tan t, csc t, sec t, and cot t.

Step-by-step explanation:

To find the values of the remaining trigonometric functions at t, we can use the given information of sin t = 5/13 and cos t = -12/13. We can use the Pythagorean identity, which states that sin2t + cos2t = 1, to find the value of sin2t. Since we know that sin t = 5/13, we can square this value to get sin2t = (5/13)2 = 25/169. Similarly, we can square the value of cos t = -12/13 to get cos2t = (-12/13)2 = 144/169.

Using these values, we can now find the remaining trigonometric functions:

  • tan t = sin t/cos t = (5/13)/(-12/13) = -5/12
  • csc t = 1/sin t = 1/(5/13) = 13/5
  • sec t = 1/cos t = 1/(-12/13) = -13/12
  • cot t = 1/tan t = 1/(-5/12) = -12/5

User Rozky
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