The sum of the coordinates of this point is 39.
Since the point (3, 6) is on the graph of y = g(x),
we know that g(3) = 6.
Substituting this into the expression for h(x),
we get h(x) = (g(x))^2 = (6)^2 = 36 for all x.
Therefore, the point (3, 36) is on the graph of y = h(x).
The sum of the coordinates of this point is 3 + 36 = 39.
Question
if the point (3,6) is on the graph of y= g(x), and h(x) = g(x))^2 for all x, then there is one point that we can determine to be on the graph of y= h(x). what is the sum of the coordinates of that point?