Question

a glass ampoule contains a ( ^32)p labeled compound with activity of 370 mbq. what energy (in joules) will be absorbed in the glass within 1 hour

Answer 1

The energy absorbed in the glass within 1 hour is 1.332 x 10^12 J.

Step-by-step explanation:

The energy absorbed in the glass can be calculated using the formula:

Energy (J) = Activity (Bq) x Time (s)

Given that the activity is 370 MBq, you need to convert it to Bq by multiplying by 106 (1 MBq = 106 Bq).

So, the activity is 370 x 106 Bq.

The time is 1 hour, which is equal to 3600 seconds.

Plugging in these values, we get:

Energy (J) = 370 x 106 Bq x 3600 s

= 1.332 x 1012 J

Therefore, the energy absorbed in the glass within 1 hour is 1.332 x 1012 J.