Question

What is the mass of 3.00x10^23 particles of water? Water has a molar mass of 18.0 g/mol.

Answer 1

8.97 g H₂O

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

3.00 × 10²³ particles H₂O

Step 2: Identify Conversions

Avogadro's Number

[Given] Molar Mass of H₂O - 18.0 g/mol

Step 3: Convert

1. Set up:
   `\displaystyle 3.00 \cdot 10^(23) \ particles \ H_2O((1 \ mol \ H_2O)/(6.022 \cdot 10^(23) \ particles \ H_2O))((18.0 \ g \ H_2O)/(1 \ mol \ H_2O))`
2. Multiply/Divide:
   `\displaystyle 8.96712 \ g \ H_2O`

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

8.96712 g H₂O ≈ 8.97 g H₂O