Question

an object is 15 cm from a diverging lens that has a focal length of -5 cm. where will the image of the object be located?

Answer 1

Using the lens formula, the image formed by a diverging lens with a focal length of -5 cm, with an object placed 15 cm from the lens, will be a virtual image located 3.75 cm behind the lens.

Step-by-step explanation:

To find the location of the image formed by a diverging lens, you can use the lens formula:

1/f = 1/do + 1/di

where:

• f is the focal length of the lens,
• do is the distance from the lens to the object, and
• di is the distance from the lens to the image.

In this case, we have:

• f = -5 cm (focal length of a diverging lens is negative),
• do = 15 cm (the object is 15 cm from the lens).

Plugging these values into the lens formula gives us:

1/(-5) = 1/15 + 1/di

This simplifies to:

-1/5 = 1/15 + 1/di

So:

1/di = -1/5 - 1/15

1/di = -3/15 - 1/15

1/di = -4/15

Therefore, di = -15/4 cm, which means the image is 3.75 cm behind the lens and virtual, since the image distance is negative for a diverging lens.