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how much work (in j) is done to accelerate a car which has a mass of 2100 kg from a speed of 20 m/s to a speed of 35 m/s?

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Final answer:

The work done to accelerate the car from a speed of 20 m/s to 35 m/s is 864750 J (joules).

Step-by-step explanation:

To calculate the work done, we can use the work-energy principle.

Work = Change in kinetic energy = (1/2) * mass * (final velocity^2 - initial velocity^2)

Given:

  • Mass of the car = 2100 kg
  • Initial velocity = 20 m/s
  • Final velocity = 35 m/s

Plugging these values into the equation:

Work = (1/2) * 2100 kg * ((35 m/s)^2 - (20 m/s)^2)

Work = (1/2) * 2100 kg * (1225 m^2/s^2 - 400 m^2/s^2)

Work = (1/2) * 2100 kg * 825 m^2/s^2

Work = 864750 J

Therefore, the amount of work done to accelerate the car from a speed of 20 m/s to 35 m/s is 864750 J (joules).

User Elie Teyssedou
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