Question

What's the probability you get AaBBCCDd from AaBBCCDd x AaBbCcDd?

Answer 1

The probability of getting the genotype AaBBCCDd from a cross between AaBBCCDd and AaBbCcDd is 1/32, calculated by multiplying the probabilities of inheriting each gene.

Step-by-step explanation:

To calculate the probability of getting the genotype AaBBCCDd from the cross AaBBCCDd x AaBbCcDd, we need to look at each gene individually using the product rule of probability.

For the A gene:

• The probability of getting A from the first parent (Aa) is 1/2.
• The probability of getting a from the second parent (Aa) is also 1/2.
• The combined probability for Aa is (1/2) x (1/2) = 1/4.

For the B gene:

• Since both parents are BB, the offspring will definitely be BB.
• The probability is 1.

For the C gene:

• The first parent can only provide a C gene.
• The second parent has a 1/2 chance of providing a C gene.
• Thus, the probability for CC is 1 x 1/2 = 1/2.

For the D gene:

• The probability of getting D from the first parent (Dd) is 1/2.
• The probability of getting d from the second parent (Dd) is also 1/2.
• The combined probability for Dd is (1/2) x (1/2) = 1/4.

Applying the product rule, multiply all the individual probabilities for each gene:

Probability(AaBBCCDd) = Probability(Aa) x Probability(BB) x Probability(CC) x Probability(Dd) = 1/4 x 1 x 1/2 x 1/4 = 1/32.

Therefore, the probability of getting the genotype AaBBCCDd from the given cross is 1/32.