Answer: 2
Step-by-step explanation:
Use the blank MO diagram (below) to aid in answering the question. Calculate the bond order for BO⁺.
B has 3 valance electrons
O has 6 valance electrons
so BO has a total of 9 electrons, but with the + 1 charge, you subtract an electron for a total of 8.
Now that you know this you can fill up your diagram as shown.
There are 8 bonding elctrons and 2 anti-bonding elctrons.
The formula for bond order is
(bonding electrons - antibonding elctrons) / (number of bonds)
thus,
(8 - 2) / (2)