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Find the sum. (b) 1+ 1/{2¹/² }+ 1/2+ 1/{2³/²}+ ............

User Cnanney
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Final answer:

To find the sum of the given series 1+ 1/{2¹/² }+ 1/2+ 1/{2³/²}+ ..., we can use the formula for the sum of an infinite geometric series.

Step-by-step explanation:

To find the sum of the given series 1+ 1/{2¹/² }+ 1/2+ 1/{2³/²}+ ..., we can rewrite each term with a common denominator and then simplify.

First, let's express each term with a common denominator of 2.

The series can be rewritten as 2/2 + 1/{2¹/² } + 1/2 + 1/{2³/²} + ..., where 2/2 is equal to 1.

Now, let's simplify each term.

The series becomes 1 + 1/{√2} + 1/2 + 1/{√8} + ...

We can observe that each term can be represented as 1/{√(2^n)}, where n starts from 0.

To find the sum of the series, we can use the formula for the sum of an infinite geometric series:

Sum = a / (1 - r), where a is the first term and r is the common ratio.

In this case, a = 1 and r = 1/√2.

Substituting the values into the formula, we get:

Sum = 1 / (1 - 1/√2).

Simplifying further, we obtain:

Sum = 1 / (1 - 1/√2) = (√2) / (√2 - 1).

User Ozke
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