Question

Assume that there are 12 map units between two loci in the mouse and that you are able to microscopically

observe meiotic chromosomes in this organism. If you examined 200 primary oocytes, in how many would you
expect to see a chiasma between the two loci mentioned above?
A) 96 B) 48 C) 6 D) 12 E) 24

Answer 1

In approximately 0.019% of the 200 primary oocytes, a chiasma would be observed between the two loci mentioned.

Step-by-step explanation:

In this case, the number of possible genetic combinations can be calculated using the formula 2^n, where n is the number of chromosomes in a set. Given that there are 12 map units between the two loci and that the organism in question is a mouse, which has 20 chromosomes in total, we can calculate the number of possible combinations as 2^20. This equals approximately 1,048,576 possible combinations.

Since there are 200 primary oocytes being examined, we can estimate the percentage of oocytes that would have a chiasma between the two loci mentioned above by dividing the number of oocytes with a chiasma by the total number of possible combinations. The calculation would be 200/1,048,576 * 100, which equals approximately 0.019%. Therefore, in approximately 0.019% of the 200 primary oocytes, a chiasma would be observed between the two loci.