The molar heat of fusion of 70 grams of Cs, given that the temperature is 1.02 °C, is 48.39 J/mol
How to calculate the molar heat of fusion of Cs?
The molar heat of fusion of 70 grams of Cs can be calculated as illustrated below:
- Temperature change (ΔT) = 1.02 °C
- Mass of Cs (m) = 70 grams
- Molar mass of Cs (M) = 132.91 g/mol
- Mole of Cs (n) = m / M = 70 / 132.91 = 0.527 mole
- Heat transferred (Q) = 25.5 J
- Molar heat of fusion of Cs (ΔHf) = ?
Heat transferred = Mole of substance × Molar heat of fusion of substance
25.5 = 0.527 × Molar heat of fusion of Cs
Divide both sides by 0.527
Molar heat of fusion of Cs = 25.5 / 0.527
Molar heat of fusion of Cs = 48.39 J/mol
Complete question:
What is the molar heat of fusion for 70 gram of Cs. Temperature delta is 1.02 °C and molar mass of cesium is 132.91 g/mol [Heat transferred = 25.5 J]