Question

0.01 × 0.9 = _______ 1 b.0.9 × 0.12 = _______ 2 a.0.04 × 0.4 = _______ 2 b.0.7 × 0.2 = _______ 3 a.0.06 × 0.4 = _______ 3 b.0.1 × 1.1 = _______ 4 a.0.4 × 0.11 = _______ 4 b.0.07 × 0.1 = _______ 5 a.0.7 × 1.2 = _______ 5 b.0.2 × 0.05 = _______ 6 a.0.06 × 0.1 = _______ 6 b.0.11 × 0.6 = _______ 7 a.1.1 × 1.2 = _______ 7 b.0.9 × 0.4 = _______ 8 a.0.6 × 0.9 = _______ 8 b.0.04 × 0.7 = _______ 9 a.0.2 × 0.1 = _______ 9 b.1.2 × 0.08 = _______ 10 a.0.4 × 0.8 = _______ 10 b.1.2 × 0.4 = _______ Page 2

Answer 1

Check below, please.

1) Let's effectuate those multiplications noticing the dot

`0.01*0.9=(1)/(100)*(9)/(10)=(9)/(1000)=0.009`

Note that since we have3 zeros on the denominator we'll have 3 decimal places, similarly:

1 b.

`0.9*0.12=\frac{_{}9}{10}*(12)/(100)=(108)/(100)=1.08`

Notice that we can write those decimal numbers as fractions.

2 a.

`0.04*0.4=(4)/(100)*(4)/(10)=(16)/(1000)=0.016`

2 b.

`0.7*0.2=_{}0.14`

3 a.

`0.06*0.4=\frac{_{}6}{100}*(4)/(10)=(24)/(1000)=0.024`

3 b.

`0.1*1.1=\frac{_{}1}{10}*(11)/(10)=(11)/(100)=0.11`

4 a.

`0.4*0.11=\frac{_{}4}{10}*(11)/(100)=(44)/(1000)=0.044`

4 b.

`0.07*0.1=_{}0.007`

5 a.

`0.7*1.2=_{}0.84`

5 b.

`0.2*0.05=_{}0.01`