From the question, we were told to find the value of three less than the quotient of six and a number increased by nine.
When n = 3.
We are to find the value of the expression.
First let's write the expression in terms of n.
recall that the expression is "three less than the quotient of six and a number, inc reased by nine".
((6 / n) - 3) + 9
We have n = 3
((6 / 3) - 3) + 9
Now let's solve the expression:
((6/3) - 3) + 9 = (2 - 3) + 9
((6/3) - 3) + 9 = (-1) + 9
((6/3) - 3) + 9 = 8
Therefore, the value of the expression is 8
So, the correct option is the third option which is 8.