Question

Consider the following function.k(x) = (x - 6)^2Step 3 of 3: Find two points on the graph of the parabola other than the vertex and x-intercepts.

Answer 1

The parabola function is given by,

`k(x)=(x-6)^2`

We need to find two points on the parabola (other than vertex and x-intercepts).

Let's take a point x = 1 and find the corresponding y value:

`\begin{gathered} k(x)=(x-6)^2 \\ y=(x-6)^2 \\ y=(1-6)^2 \\ y=(-5)^2 \\ y=25 \end{gathered}`

So, the point is (1, 25)

Now, let's take another random x value of x = 2,

So, the corresponding y value is:

`\begin{gathered} k(x)=(x-6)^2 \\ y=(x-6)^2 \\ y=(2-6)^2 \\ y=(-4)^2 \\ y=16 \end{gathered}`

The other point is (2, 16)

Answer(s)
`\begin{gathered} (1,25) \\ (2,16) \end{gathered}`