Final answer:
The force on each pillar supporting the bridge and car can be found by dividing the weight between them. The force on the pillar supporting the car is 9408 N, while the force on each of the pillars supporting the bridge is 7056 N.
Step-by-step explanation:
To determine the force on each pillar, we need to consider the weight of the bridge and the car. The weight of an object is equal to its mass multiplied by the acceleration due to gravity. In this case, the weight of the bridge is 2400 kg multiplied by 9.8 m/s^2, which gives us 23,520 N. The weight of the car is 960 kg multiplied by 9.8 m/s^2, which gives us 9408 N.
The force on each pillar can be calculated by dividing the weight between them. Since the car is parked 5.0 m from one end, the weight of the car will only be exerted on one pillar. So, the force on that pillar would be 9408 N. The remaining weight of the bridge, 23,520 N - 9408 N = 14,112 N, will be evenly distributed between the two pillars, resulting in a force of 14,112 N / 2 = 7056 N on each of them.
Therefore, the force on the pillar supporting the car would be 9408 N, while the force on each of the pillars supporting the bridge would be 7056 N.