Final answer:
The aerobic catabolism of one glucose molecule generates a theoretical maximum of 38 ATP, with 4 ATP from substrate-level phosphorylation and 34 from oxidative phosphorylation. However, the actual yield can be lower.
Step-by-step explanation:
Aerobic metabolism of one molecule of glucose through glycolysis, pyruvate oxidation, and the citric acid cycle generates a significant amount of ATP.
Detailed accounting:
- Glycolysis:
- Gross production: 4 ATP
- Net production (accounting for the 2 ATP used to start glycolysis): 2 ATP - Transition Reaction (pyruvate to acetyl-CoA):
- Per glucose molecule, 2 NADH are produced, each resulting in the generation of 3 ATP (Total: 6 ATP) through the electron transport chain. - Citric Acid Cycle (per two turns, since each glucose results in two acetyl-CoA):
- ATP production by substrate-level phosphorylation: 2 ATP
- NADH production (3 NADH per cycle x 2 cycles): 6 NADH → 18 ATP
- FADH₂ production (1 FADH₂ per cycle x 2 cycles): 2 FADH₂ → 4 ATP - Oxidative Phosphorylation:
- From NADH and FADH₂ produced in previous steps: 10 NADH → 30 ATP and 2 FADH₂ → 4 ATP (via the electron transport chain)
This brings the theoretical total amount of ATP produced from one glucose molecule to 4 ATP (substrate-level phosphorylation) and 34 ATP (oxidative phosphorylation), yielding a maximum of 38 ATP. However, the actual yield is often lower due to various factors.