Final answer:
To find the number of moles of oxygen needed to react with 9.30 moles of acetylene, we first balance the combustion equation to C2H2 + O2 → CO2 + H2O and determine the stoichiometric coefficients. We use these coefficients to set up a ratio and calculate that 23.25 moles of oxygen are required for the reaction.
Step-by-step explanation:
The student is asking how many moles of oxygen (O₂) are needed to completely react with 9.30 moles of acetylene (C₂H₂) in a combustion reaction. To answer this, we need to first balance the chemical equation:
C₂H₂ + O₂ → CO₂ + H₂O
After balancing, the equation looks like this:
2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O
This balanced equation tells us that 2 moles of acetylene require 5 moles of oxygen to react completely. To find out how many moles of oxygen are required for 9.30 moles of acetylene, we can set up a simple proportion:
(9.30 moles C₂H₂) × (5 moles O₂ / 2 moles C₂H₂) = 23.25 moles O₂
Therefore, 23.25 moles of oxygen are required to completely react with 9.30 moles of acetylene.