Final answer:
In 4.0 seconds, an object in free-fall near Earth's surface will be falling at approximately 40 m/s, when considering Earth's gravity as 9.80 m/s².
Step-by-step explanation:
The question relates to an object's velocity during free-fall under the influence of Earth's gravity, which is assumed to be a constant acceleration of 9.80 m/s². The velocity of an object in free-fall can be calculated using the formula v = g × t, where v is the final velocity, g is the acceleration due to gravity, and t is the time. After 4.0 seconds, the object's velocity can be calculated as v = 9.8 m/s² × 4.0 s = 39.2 m/s. However, since the available options do not include 39.2 m/s, the closest approximate answer is 40 m/s (Option 1).