Question

Which equation represents a line which is perpendicular to the line y=2/5x-81. y=2/5x-32. y=5/2x-13. y=-2/5x+64. y=-5/2x+9

Answer 1

The slope-intercept form of the line is given by:

`\begin{gathered} y=mx+b \\ m=slope \\ b=y-intercept \end{gathered}`

for the line:

`y=(2)/(5)x-8`
`m=(2)/(5)`

If two lines are perpendicular, then:

`\begin{gathered} m1* m2=-1 \\ so\colon \\ (2)/(5)* m2=-1 \\ m2=-(1)/((2)/(5)) \\ m2=-(5)/(2) \end{gathered}`

Therefore, the equation that represents the line perpendicular to the line y = 2/5x - 8 is:

`y=-(5)/(2)x+9`