Question

Final Grade An instructor grades exams, 30%; term paper, 30%; and final exam, 40%. A student had grades of 88, 90, and 96, respectively, for exams, terpaper, and final exam. Find the student's final average. Use the weighted mean.

Answer 1

`\bar{x}=91.8`

Explanation:

Grades respectively:

30% Grades exams: 88

30% Term paper: 90

40% Final exam: 96

The weighted mean is represented by the following equation:

`\bar{x}=\frac{\sum ^{}_{}(wx)}{\sum ^{}_{}w}`

Therefore, the student's final average would be:

`\begin{gathered} \bar{x}=(0.3\cdot88+0.3\cdot90+0.4\cdot96)/(1) \\ \bar{x}=91.8 \end{gathered}`