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What is the value of the 4th term of the expansion of (y+2z)^8

User Wendy Liga
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1 Answer

1 vote

Answer:

448y^5z^3.

Explanation:

(r+1)the term of (a + b)^n

= nCr a^(n-r) b^r

So here we have

4th term = 8C3 y^(8-3) (2z)^3

= 56y^5*8z^3

= 448y^5z^3.

User Wim Leers
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