Question

Question 9 of 10Which equation shows that the Pythagorean identity is true for = 3 ?Select the equation that is in the form sin² (3³) + cos² (³) = 1.O A. 1² +0² = 1O B. (-1)2 +0²= 1O c. 0² + (-1)² = 1OD. 02 +12 - 1=

Answer 1

Given:

`sin^2((3\pi)/(2))+cos^2((3\pi)/(2))=1`

Find: equation represents pythagorean property.

Explanation:

`\begin{gathered} sin^2((3\pi)/(2))+cos^2((3\pi)/(2))=1 \\ sin^2(\pi+(\pi)/(2))+cos^2(\pi+(\pi)/(2))=1 \\ sin^2((\pi)/(2))+cos^2((\pi)/(2))=1 \\ 1^2+0^2=1 \end{gathered}`

Final answer: the required equation is

`1^2+0^2=1`