Question

Simply the expression below, assume the denomination does not equal zero

Answer 1

`(2x+1)/(x+5)`

Step-by-step explanation

To simplify this expression, we will factorize each of these equations

6x² - 7x - 5

= 6x² - 10x + 3x - 5

= 2x (3x - 5) + 1 (3x - 5)

= (2x + 1) (3x - 5)

3x² + 10x - 25

= 3x² + 15x - 5x - 25

= 3x (x + 5) - 5 (x + 5)

= (3x - 5) (x + 5)

So, we can write the expression and simplify below

`\begin{gathered} (6x^2-7x-5)/(3x^2+10x-25) \\ =\frac{(2x+1)(3x-5)_{}}{(3x-5)(x+5)} \\ \text{The (3x - 5) in both numerator and denominator cancels out and we have} \\ (2x+1)/(x+5) \end{gathered}`

Hope this Helps!!!