Question

The airplane starts from rest and accelerates east at a constant 3.00 m/s² for 30.0 s before leaving the ground. What is the final velocity of the airplane?

1) 0 m/s
2) 30 m/s
3) 90 m/s
4) 300 m/s

Answer 1

The final velocity of the airplane after accelerating east at a constant 3.00 m/s² for 30.0 s from rest is 90 m/s.

Step-by-step explanation:

To calculate the final velocity of the airplane, we can use the basic kinematic equation for constant acceleration, which is v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Since the airplane starts from rest, the initial velocity u is 0 m/s. The acceleration a given is 3.00 m/s², and the time t is 30.0 s. Plugging these values into the equation, we get: v = 0 m/s + (3.00 m/s²)(30.0 s), which results in v = 90.0 m/s. Therefore, the correct answer is 90 m/s.