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Suppose a random variable x has a mean of 112 and a standard deviation of 10 and a random variable y has a mean of 36 and a standard deviation of 4. Assume x and y are independent. If a new random variable z is defined as 3y – 12, what is the standard deviation of z?

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Final answer:

The standard deviation of the transformed variable z, defined as 3y − 12, is calculated by multiplying the coefficient of the transformation (3) by the standard deviation of y (4), which results in a standard deviation of 12 for z.

Step-by-step explanation:

If you have a new random variable z defined as 3y − 12, where y is a random variable with a mean of 36 and a standard deviation of 4 and assuming that x and y are independent, then the transformation affects only the mean and the standard deviation of y. The transformation does not affect variable x since it is independent of y.

The formula for the standard deviation of z after the transformation is σz = |a|σy, where σy is the standard deviation of y, and a is the coefficient of y in the transformation. In this case, a=3.

Therefore, the new standard deviation of the transformed variable z is given by:

σz = |3|σy
= 3 × 4
= 12

The standard deviation of the new random variable z is 12.

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