Final answer:
The equation √(2x³) - √(x²) = 0 has no solution, as the potential answer x = 0.50 is extraneous when checked against the original equation.
Step-by-step explanation:
To solve the radical equation √(2x³) - √(x²) = 0, we first isolate one of the radicals:
√(2x³) = √(x²)
Squaring both sides to eliminate the radicals gives us:
2x³ = x²
Dividing both sides by x², assuming x is not equal to 0, simplifies to:
2x = 1
So the solution for x is:
x = ½ or 0.50 when rounded to the nearest hundredth.
We need to check that this solution is not extraneous. Substituting x back into the original equation:
√(2(0.50)³) - √(0.50²) = √(0.50) - √(0.25)
0.71 - 0.50 = 0.21 ≀ 0
Since the check does not result in a true statement, the solution x = 0.50 is extraneous and there is no solution to the equation.