Final answer:
To make a 500 mL solution with a 70% ethanol concentration, you need 350 mL of absolute ethanol and 150 mL of water.
Step-by-step explanation:
To create a 500 mL solution with a 70% concentration of ethanol (C₂H₅OH), you need to calculate the volume of absolute ethanol that would result in such a concentration. The calculation is straightforward:
- Volume of solution required = 500 mL
- Desired concentration of solution = 70%
Therefore, you need 70% of the 500 mL to be ethanol which is:
- 0.70 x 500 mL = 350 mL of ethanol
So, to make a 500 mL solution that is 70% ethanol, you would need 350 mL of absolute ethanol and the remaining 150 mL would be water to make up the total volume to 500 mL.