Final answer:
The heat lost when the 64g piece of copper cools from 375°C to 26°C is -8764.32 J.
Step-by-step explanation:
The amount of heat lost when a 64g piece of copper cools from 375°C to 26°C can be calculated using the equation:
q = mcΔT
where q is the heat lost, m is the mass of the copper (in grams), c is the specific heat capacity of copper (0.39 J/g°C), and ΔT is the change in temperature.
Substituting the given values:
-
- m = 64g
-
- c = 0.39 J/g°C
-
- ΔT = (26°C - 375°C) = -349°C
we can calculate the heat lost:
q = (64g)(0.39 J/g°C)(-349°C) = -8764.32 J
Therefore, the heat lost when the 64g piece of copper cools from 375°C to 26°C is -8764.32 J.