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How many grams of calcium phosphate would be equal to 4.5 moles of calcium phosphate?

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Final answer:

To find the mass of 4.5 moles of calcium phosphate, multiply the number of moles (4.5) by its molar mass (310.18 g/mol), which gives a result of 1395.81 grams.

Step-by-step explanation:

To calculate the mass of 4.5 moles of calcium phosphate (Ca3(PO4)2), we need to determine the formula mass of calcium phosphate. The formula mass is calculated by adding together the atomic masses of the constituent elements, which includes three calcium atoms, two phosphorus atoms, and eight oxygen atoms:

  • Calcium (Ca) atomic mass = 40.08 g/mol
  • Phosphorus (P) atomic mass = 30.97 g/mol
  • Oxygen (O) atomic mass = 16.00 g/mol

Therefore, the formula mass is:
3(Ca) + 2(P) + 8(O) = 3(40.08 g/mol) + 2(30.97 g/mol) + 8(16.00 g/mol) = 310.18 g/mol for calcium phosphate.

To find the mass in grams for 4.5 moles:

Mass = moles × molar mass
Mass = 4.5 moles × 310.18 g/mol = 1395.81 grams

Thus, 4.5 moles of calcium phosphate would be equal to 1395.81 grams of calcium phosphate.

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