Final answer:
To find the number of ways to choose a subset of two juniors, the combination formula C(n, 2) = n! / (2!(n - 2)!) is used. The order does not matter in this selection, and the result gives the total amount of possible unique pairs.
Step-by-step explanation:
Calculating Combinations
To determine the number of ways to choose a subset of two juniors from a larger group, we use the concept of combinations from mathematics. A combination is a selection of items where the order does not matter. If we have n juniors, the number of ways to choose two of them is given by the combination formula:
C(n, 2) = n! / (2!(n - 2)!)
where C(n, 2) represents the number of combinations of n items taken two at a time, and n! (n factorial) is the product of all positive integers up to n. For example, if there are 10 juniors, applying the formula yields:
C(10, 2) = 10! / (2!(10 - 2)!) = (10 × 9) / (2 × 1) = 45
Thus, there would be 45 ways to choose a subset of two juniors from a group of ten. Replace 10 with the actual number of juniors to get the specific answer.