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A dentist drill starts at rest and spins up to 12,000 rpm in 2.1 seconds and then remains at that level for 20 seconds. (a) What are the drill's initial and final angular speeds (in rad/sec)? (b) Find the drill's angular acceleration during spin-up. (c) What is the total number of revolutions the drill rotates in the total time?

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Final answer:

The initial angular speed of the dentist drill is 0 rad/s and the final angular speed is 800π rad/s. The angular acceleration during spin-up is 800π/2.1 rad/s². The drill rotates a total of 8000 revolutions in 20 seconds.

Step-by-step explanation:

(a) To find the initial and final angular speeds of the dentist drill, we need to convert the rpm values to radians per second (rad/s).
The initial angular speed of the drill can be calculated by multiplying the initial rpm value by 2π/60, since 1 revolution = 2π radians and 1 minute = 60 seconds. So, the initial angular speed is:

Initial angular speed = (0 rpm) * (2π/60 rad/s per rpm) = 0 rad/s.

The final angular speed can be calculated in the same way, using the value of 12,000 rpm:

Final angular speed = (12,000 rpm) * (2π/60 rad/s per rpm) = 800π rad/s.

(b) The angular acceleration during spin-up can be found using the formulas:

Angular acceleration = (change in angular speed) / (change in time).

During spin-up, the change in angular speed is the final angular speed minus the initial angular speed, and the change in time is the spin-up time of 2.1 seconds. So, the angular acceleration is:

Angular acceleration = (800π rad/s - 0 rad/s) / 2.1 s = (800π / 2.1) rad/s².

(c) The total number of revolutions the drill rotates in the total time can be calculated by multiplying the final angular speed by the total time:

Total number of revolutions = (800π rad/s) * (20 s) / (2π rad per revolution) = 8000 revolutions.

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