Question

A car moves with constant velocity along a straight road. Its position is x1 = 0 m at t1 = 0 s and is x2 = 30 m at t2 = 3.0 s. What is the car's position at t = 1.5 s?

Answer 1

The car's position at t = 1.5 s, with constant velocity, is calculated to be 15 meters using the equations of motion for uniform velocity.

Step-by-step explanation:

The car moves with a constant velocity along a straight road. Given the positions and times (x1 = 0 m at t1 = 0 s, and x2 = 30 m at t2 = 3.0 s), we can determine the velocity using the formula v = Δx / Δt which yields a velocity of 10 m/s. To find the car's position at t = 1.5 s, we can use the equation for uniform motion, x = x0 + vt. Since x0 = 0 m and v = 10 m/s, substituting t = 1.5 s, we get x = 0 m + 10 m/s × 1.5 s which equals 15 m. Therefore, the car's position at t = 1.5 s is 15 meters.