Question

A batter hits a baseball m = 0.41 kg from rest with a force of f = 81 n, the ball is in contact with the bat for t = 0.22 s. it is observed that the ball leaves the bat with an angle of 0 = 29 degrees with respect to the horizontal. How far did the ball travel horizontally in meters?

Answer 1

The ball travels approximately 6.37 meters horizontally.

Step-by-step explanation:

To determine the horizontal distance the ball travels, we can use the equations of motion. We know that the initial velocity in the horizontal direction is 0 m/s because the ball is hit from rest. The equation to calculate the horizontal distance is:

d = v * t * cos(theta)

Where d is the horizontal distance, v is the final velocity in the horizontal direction, t is the time of motion, and theta is the angle with respect to the horizontal.

In this case, we are given the final velocity v = 30 m/s, the time t = 0.22 s, and the angle theta = 29 degrees. Plugging these values into the equation, we get:

d = 30 m/s * 0.22 s * cos(29 degrees)

Solving for d, we find that the ball travels approximately 6.37 meters horizontally.