Question

Given the generic balanced reaction equation 2a + 7b → 5c + 6d, how many moles of c can be produced when 3.80 moles of a are reacted with excess moles of b?

Answer 1

When 3.80 moles of a are reacted with excess moles of b, 9.50 moles of c can be produced.

Step-by-step explanation:

In order to determine how many moles of c can be produced when 3.80 moles of a are reacted with excess moles of b, we need to determine the mole ratio between a and c. From the balanced equation 2a + 7b → 5c + 6d, we can see that the mole ratio of a to c is 2:5. Therefore, for every 2 moles of a that react, we can produce 5 moles of c. With 3.80 moles of a, we can calculate the number of moles of c as follows:

Moles of c = (3.80 moles of a) * (5 moles of c / 2 moles of a) = 9.50 moles of c

Therefore, when 3.80 moles of a are reacted with excess moles of b, 9.50 moles of c can be produced.