Question

A 15.9-kg mass fastened to the end of a steel wire with an unstretched length of 0.500 m is whirled in a vertical circle with angular velocity 2.50 rev/s at the bottom of the circle. The cross-sectional area of the wire is 1.50×10-2 cm2. What is the tension in the wire at the bottom of the circle?

Answer 1

The tension in the wire at the bottom of the circle is approximately 192 N.

Step-by-step explanation:

To calculate the tension in the steel wire, we can use the equation:

Tension = mass * (angular velocity)^2 * radius + mg

Where:

• mass = 15.9 kg
• angular velocity = 2.50 rev/s
• radius = unstretched length = 0.500 m
• g = acceleration due to gravity = 9.81 m/s²

Substituting the values into the equation, we get:

Tension = 15.9 kg * (2.50 rev/s)^2 * 0.500 m + 15.9 kg * 9.81 m/s²

Simplifying the equation, we find that the tension in the wire at the bottom of the circle is approximately 192 N.