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A 40kg child was riding a merry go round at a speed of 2.9m/s meters from the center. What is the acceleration of the child as he is thrown from the playground equipment?

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Final answer:

The acceleration of the child as he is thrown from the playground equipment can be calculated using the centripetal acceleration formula, which is a = v^2 / r. Plugging in the values, the acceleration of the child is 2.9 m/s^2.

Step-by-step explanation:

The acceleration of the child as he is thrown from the playground equipment can be calculated using centripetal acceleration formula. Centripetal acceleration (a) is given by the equation

a = v^2 / r

where v is the velocity of the child and r is the distance from the center.

Plugging in the values, we have:

a = (2.9 m/s)^2 / 2.9 m = 2.9 m/s^2

Therefore, the acceleration of the child is 2.9 m/s^2.

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