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A 1.0-l buffer solution is 0.120 m in HNO₂ and 0.195 m in NaNO₂. Determine the concentrations of HNO₂ and NaNO₂ after the addition of 1.3 g HI?

User Valin
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Final answer:

To dilute 1.88 M HNO3 to prepare 0.125 M HNO3, use the dilution formula M1V1 = M2V2, resulting in the required volume of 16.6 mL of the original solution.

Step-by-step explanation:

To prepare a 0.125 M HNO3 solution from a more concentrated 1.88 M HNO3, you need to perform a dilution calculation. The volume of the 1.88 M solution that is needed can be found using the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

The final volume (V2) we aim for is the product of the final molarity (M2) and the volume of 1.88 M HNO3 (V1) divided by the initial molarity (M1). So, the necessary volume of 1.88 M HNO3, V1, is calculated as:

V1 = (M2 × V2) / M1

V1 = (0.125 M × 0.250 L) / 1.88 M = 0.0166 L or 16.6 mL

User Caleb Bergman
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