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At equiLiBrium, the value of [H⁺ ] in a 0.260M solution of an unknown acid is 0.00412M. Determine the degree of ionization and the Ka of this acid.

User DavSanchez
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Final answer:

The degree of ionization for the unknown acid is 1.585%, and the Ka of the acid is approximately 6.68 x 10^-5.

Step-by-step explanation:

The degree of ionization of an acid is the fraction of the total acid that has ionized in solution. It can be calculated as the concentration of ionized hydrogen ions [H+] divided by the initial concentration of the acid. In this case, the degree of ionization is 0.00412 M / 0.260 M, which equals approximately 0.01585 or 1.585%.

To determine the acid dissociation constant (Ka) for the unknown weak acid, we use the formula Ka = [H+]^2 / [Acid], where [Acid] is the concentration of the undissociated acid. The concentration of the undissociated acid can be found by subtracting the ionized hydrogen concentration from the initial concentration of the acid ([Acid] = 0.260 M - 0.00412 M). Thus, the Ka is (0.00412 M)^2 / (0.25588 M) which gives us a Ka approximately equal to 6.68 x 10-5.

User Gython
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