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A storeowner mixed 8 pounds of peanuts and 5 pounds of ________ sold for $55.27.

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Final answer:

The student's question involves calculating the weight of an item combined with 8 pounds of peanuts to reach a sale price of $55.27, where we assume the unknown item is also priced at $3.25 per pound. This results in approximately 9 pounds of the second item mixed with the peanuts to achieve the total sale price.

Step-by-step explanation:

The original question seems to be missing some information, but based on what is provided, I believe you are trying to determine what mixed with 8 pounds of peanuts could have been sold for a total of $55.27. To solve this, we need to know the price per pound of the other item mixed with the peanuts. If we assume the other item is also sold at $3.25 per pound, then we can calculate the total weight of that item needed to reach the final sale price.

To calculate, we first establish the total cost of the peanuts:

  • 8 pounds of peanuts at $3.25 per pound

This results in $26 for the peanuts (8 pounds * $3.25 per pound = $26). Next, we subtract that from the total sale price to find out how much of the remaining price needs to be accounted for the second item:

$55.27 total sale price - $26.00 for peanuts = $29.27

Now we divide the remaining cost by the price per pound of the second item. Assuming it is also $3.25 per pound, we get:

$29.27 / $3.25 per pound = approximately 9 pounds

Therefore, the storeowner could have mixed 8 pounds of peanuts with approximately 9 pounds of another item, sold at $3.25 per pound, to reach the total sale price of $55.27.

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