Question

A sinusoidal transverse wave travels along a stretched string. The amplitude of this wave is 0.0889m and its frequency is 3.13 Hz and its wavelength is 1.75 m. What is the shortest distance between a maximum and minimum of the wave?

Answer 1

The shortest distance between a maximum and a minimum of the sinusoidal transverse wave with a wavelength of 1.75 m is half the wavelength, which is 0.875 m.

Step-by-step explanation:

The question asks, "What is the shortest distance between a maximum and minimum of the wave?" In a sinusoidal transverse wave, the shortest distance between a maximum (peak) and a minimum (trough) is half the wavelength, as these points are one-half of a full wave cycle apart. Since the given wavelength of the wave is 1.75 m, the shortest distance between a maximum and a minimum, also known as the half-wavelength, is 1.75 m / 2, which equals 0.875 m.